| nextnano3 - Tutorialnext generation 3D nano device simulator2D TutorialSingle-band ('effective-mass') is a special case of 8-band k.p ('8x8kp') if the 
electrons are decoupled from the holesAuthor:
Stefan Birner If you want to obtain the input file that is used within this tutorial, please 
submit a support ticket.
 -> effective_mass_vs_8x8kp_sg_2D.in-> effective_mass_vs_8x8kp_kp_2D.in
 -> effective_mass_vs_8x8kp_density_sg_2D.in
 -> effective_mass_vs_8x8kp_density_kp_2D.in
 -> effective_mass_vs_8x8kp_same_mass_sg_2D.in
 -> effective_mass_vs_8x8kp_same_mass_kp_2D.in
 
 1) Single-band ('effective-mass') is a special case of 8-band k.p ('8x8kp') if the 
electrons are decoupled from the holesInput file -> 2Deffective_mass_vs_8x8kp.in Note: This tutorial is identical to the 1D 
tutorial "Single-band ('effective-mass') is a special case of 8-band k.p ('8x8kp') if the 
electrons are decoupled from the holes".The only difference is that it is 2D.
 In 1D, the simulated structure is 45 nm long.In 2D, the simulated structure is 45 nm long and 5 nm wide (y axis). Along the y 
axis, we apply periodic boundary conditions to the Schrödinger equation, so that 
the structure is effectively infinitely long.
 Results
  The following figure shows the conduction band profile and the three 
  lowest (confined) eigenstates for k=0 including their charge densities (wave function 
  Psi²) for a 5 nm AlAs/GaAs quantum well.
 1D plot of the 1D tutorial:
 
 
  2D plot of the 2D tutorial:
 
 
  
 The scale on the left corresponds to the conduction band edge energies of the 
  barrier (4.049 eV) and the well (2.979 
  eV).
 We want to stress that we solved a two-dimensional Schrödinger equation in 2D 
and not only a one-dimensional one as in 1D. The calculated eigenvalues can be found in the files1D:
 
Schroedinger_1band/ev1D_cb001_qc001_sg001_deg001_dir   _Kx001_Ky001_Kz001.dat2D:
  
Schroedinger_1band/ev2D_cb001_qc001_sg001_deg001_dirper_Kx001_Ky001_Kz001.dat
                                         
dirichlet   boundary condition along x
                                        
   periodic boundary condition along y 
  
    |  | 1D eigenvalues: | 2D eigenvalues: | 2D eigenvalues: | 2D eigenvalues (k.p): |  
    | schroedinger-masses-anisotropic |  | = no | = box | - |  
    | schroedinger-kp-discretization |  | - | - | = box-integration |  
    | e1 = | 3.09100 eV | 3.09100 | 3.0908 | 3.09100 |  
    | e2 = | 3.43473 eV | 3.43473 | 3.4341 | 3.43473 |  
    | e3 = | 3.97526 eV |         3.97526
    (7th ev) |         
	3.9740 (5th ev) |          3.97526 
	(10th ev) |  Both, 1D and 2D, and both,
 effective-mass and 
8x8kp lead to exactly the same eigenvalues. Also the squared wave functions 
(Psi²) are identical. The squared wave functions are normalized in units of 
[1/nm²] so that they integrate to 1.0 if the integration interval is over the 
area from 10 
nm to 35 nm along the x axis and from 0 nm to 5 nm along the y axis. (The 
rectangle of the quantum cluster extends from 10 nm to 35 nm along x and from 0 
nm to 5 nm along y.) Note that the probabilities Psi² are shifted by the 
corresponding eigenvalues so that they fit nicely into the graph. Here, the 
color dark blue corresponds to zero 
probability of Psi².
 Note:Single-band
 
 - schroedinger-masses-anisotropic = yes: Periodic boundary 
conditions not implemented yet.
 - schroedinger-masses-anisotropic = box: Periodic boundary 
conditions implemented but do not work if the quantum cluster coincides with the 
whole device volume:
   'Error get_sg_material_parameters: i_material out of range.'Thus the quantum region has to be reduced to a length of 4 nm, 
i.e. from 0 to 4 nm (if the gridding is in steps of 1 nm) because '
box'
   assumes that there is an additional grid point between 4 nm 
and 0 nm when applying periodic boundary conditions.8-band k.p
 - schroedinger-kp-discretization = finite-differences: Periodic boundary 
conditions not implemented yet.: Periodic boundary 
conditions implemented but do not work if the quantum cluster coincides with the 
whole device volume:- schroedinger-kp-discretization = box-integration
   'Error get_8x8_kp_zb_parameters: Number of point out of range.'
   Thus the quantum region has to be reduced to a length of 4 
nm, i.e. from 0 to 4 nm (if the gridding is in steps of 1 nm) because 'box-integration'
   assumes that there is an additional grid point between 4 nm 
and 0 nm when applying periodic boundary conditions.   
 2) Calculating the quantum mechanical density within the single-band 
approximation and 8-band k.p self-consistentlyInput file -> 2Deffective_mass_vs_8x8kp_density.in Our input file contains a similar 5 nm quantum well but instead of AlAs we 
take Al0.2Ga0.8As as the barrier material. However, this 
time we include some n-type doping with a concentration of 1*1017 cm-3. 
Only the AlGaAs region between 35 and 40 nm (along the x axis) is doped. The donor atom has a donor 
level of 0.007 eV below the conduction band. We use flow-scheme = 2, i.e.- we solve the Poisson equation including doping to obtain the electrostatic 
potential
 - we use this electrostatic potential to solve Schrödinger's equation 
effective-mass (single-band) approximation
 - we calculate the electron density (including quantum mechanical density) that 
enters the Poisson equation
 - we solve the Poisson and Schrödinger equation self-consistently
 The following figure shows the conduction band profile and the lowest 
eigestate as well as its probability amplitude. The chemical potential (i.e. the 
Fermi level) is not shown in the figure. It is equal to 0 eV. There are no 
further eigenstates that are confined inside the well. (The figure also shows 
the k.p results which are identical.) 
  1D plot of the 1D tutorial:
  
  2D plot of the 2D tutorial:
 
  
 The scale on the left corresponds to the conduction band edge energies of the 
  barrier and the well 
in units of [eV].
 Note: In our example we take into account only the first quantized 
eigenstate. Usually one has to sum over all (occupied) eigenstates to calculate 
the quantum mechanical density. The three-dimensional electron density of this 2D quantum structure 
(homogeneous along the z direction) can be calculated 
in the single-band effective-mass approximation (i.e. parabolic and isotropic bands) as 
follows: 1D: n(x) = g m||,av kBT / (2 pi hbar²) |Psi1(x)|² 
ln(1 + exp( (EF(x) - E1)/ (kBT) ) )Note the squared wave function |Psi1|² must be normalized over the 
length of the quantum cluster, i.e. the units are 1/m.
 2D: n(x,y) = 1/2 g [ mz,av kBT / (2 pi hbar²) 
]1/2 |Psi1(x,y)|² F-1/2[ 
(EF(x,y) - E1)/ (kBT) ]Note the squared wave function |Psi1|² must be normalized over the 
area of the quantum cluster, i.e. the units are 1/m².
 (For 1D, confer also the corresponding equation in the overview section: "Purely 
quantum mechanical calculation of the density".) 
  g is the degeneracy factor for both spin and valley degeneracy. In our 
  case, the Gamma conduction band valley is not degenerate, so we have g = 2 to 
  account for spin degeneracy.Usually mz depends on the grid point (x,y), so we should have 
  written mz(x,y) instead of mz,av. However, this leads to 
  discontinuities in the quantum charge density as mz(x,y) is 
  discontinuous at material interfaces. A possible solution is to take an 
  average of all mz values in the quantum cluster weighted by the 
  quantum charge density (Psi²). This leads to mz,av = 
  0.0698246 (1D: m||,av = 0.0698240)kBT = 0.025852 eV (at 300 K)[m0 kBT / (2 pi hbar²) ]1/2 = 
  2.323704676 * 108 1/mNote that: [kg VAs / (J²s²)]1/2 = [Ns²/m / (Js²)]1/2 = [N/m / J]1/2 = [1 / m²]1/2 
  = [1/m]
|Psi1(x,y)|²: Probability amplitude of the wave function Psi1 
  of the first eigenstate.The maximum value of |Psi1(x=22.5 nm,y)|² is 0.04247 1/nm².
 This value, multiplied with the length of 5 nm (extension along the y 
  direction) leads to 0.21235 1/nm and compares well with the 1D result of 
  0.21237 1/nm.
EF(x,y): Chemical potential (i.e. Fermi level). In our example it 
  is equal to zero: EF(x,y) = 0E1 = 0.08366 eV: energy of the first quantized state (1D: E1 = 0.07117 eV) The Fermi-Dirac integral F-1/2 (which includes the Gamma prefactor 
of the Fermi-Dirac integral) at position (x=22.5 nm,y) can be 
evaluated to: F-1/2 [ 
(EF(x,y) - E1)/ (kBT) ] = F-1/2 [ 
-3.236173 ] = 0.0382551
 We calculate the electron density for the grid point in the middle of the quantum well where 
the maximum of the probability amplitude occurs: => n(x = 22.5 nm,y) = 1/2 * 2 * (0.069824)1/2 * 2.323704676*108 1/m * 0.04247 1/nm² * 
0.0382551 = 9.9976 * 1022 1/m³ This number divided by the three-dimensional number density (1*1024) 
leads to 0.09976, i.e. the output is in units of 1 * 1018 cm-3, 
thus the density equals 0.09976 * 1018 cm-3 (1D result: 
0.09893 * 1018 cm-3) This value is in agreement with the plot of the electron density. The density 
is dominated by the quantum mechanical contribution to the density. The 
classical contribution is negligible (i.e. only 0.00007 * 1018 cm-3). 2D plot of the self-consistent electron charge density:
 
  
 On the left side the figure shows the color map of the electron density (in 
units of 1 * 1018 cm-3). Note that the color of the 
conduction band edge has nothing to do with it.
 Compare to the 1D plot of the corresponding 1D tutorial:
 
    
 
3) Calculation of the quantum mechanical density from the k.p dispersion (no 
self-consistency)Input file -> 2Deffective_mass_vs_8x8kp_same_mass.in 
To compare the k.p results with the effective-mass results it is easier 
to use for both materials the same conduction band effective mass. So even for 
Al0.2Ga0.8As we take the GaAs mass of 0.067 this time. The 
relevant 8-band k.p parameter S is then given by S = 1/me = 
1/0.067 = 14.925. 
We use the same doping as in 2) but this time we use flow-scheme =
3, i.e.- we solve the Poisson equation including doping to obtain the electrostatic 
potential
 - we use this electrostatic potential to solve Schrödinger's equation with both 
effective-mass (single-band) approximation and 8-band k.p. As expected the 
eigenvalues and wave functions coincide for these two cases. The energy of the 
lowest eigenstate is E1 = 0.10707 eV (1D: E1 = 0.10707).
 
Here is the 1D plot of the corresponding 1D tutorial (which is identical to the 
2D case): 
 In order to calculate the k.p dispersion E(kz), 
we have to solve the 8-band k.p Hamiltonian for different kz (in-plane wavevector). As our electrons in the Hamiltonian are 
decoupled from the holes, we have the special case where the dispersion E(kz) is 
parabolic. In 2D, the k.p dispersion is "isotropic" in any case as we 
only have one direction. Thus it is possible to 
plot (and calculate) the E(kz) dispersion along a line only. In 1D, 
we had a 2D k space. num-kp-parallel = 15Our k space, i.e. k=kz, 
contains 15 k points in the 1D Brillouin zone. Thus it is sufficient to integrate over the k 
points that are lying along the line of the 1D Brillouin zone.
 The relevant data for the E(kz) dispersion along the 
kz direction is stored 
in the file: Schroedinger_kp/kpar2D_dispel_ev001.datIt contains 15 k points and the corresponding eigenvalues.
 The parabolic dispersion is given by E(kz) = E1 + hbar²/2m0 
kz²/mcwhere hbar²/2m0 is given by 3.81 [eV Angstrom²] and 
the conduction band effective mass mc is a dimensionless quantity 
here in this equation. kz is given in [1/Angstrom]. E1 is 
the energy of the lowest eigenstate E1 = 0.10707 eV (1D: E1 = 
0.10707 eV). As expected, the 
dispersion for the effective-mass approximation agrees perfectly to the 8-band 
k.p case.
 
 
To calculate the k.p densities one has only one option to choose from so 
far for 
the integration over the 1D Brillouin zone:
 method-of-brillouin-zone-integration = special-axis(not implemented yet)= gen-dos
(not applicable to a 2D 
simulation)= simple-integration
 
  special-axis uses a 1D integration 
  along a line. The number of kz points is taken from the input file 
  (num-kp-parallel = 15).gen-dos calculates the density 
  of states (DOS) and integrates over the DOS for obtaining the k.p 
  density. More details can be found in the
glossary. The following figure compares the quantum mechanical electron charge 
densities calculated with the effective-mass 
approximation and with k.p. 1D plot 
 
2D plot 
 Here, the 2D k.p and single-band densities are in perfect agreement. 
Only 4 kz points are necessary. However, the 2D density is different 
compared to the 1D case although the conduction bands, the eigenvalues, psi² and 
effective masses are in perfect agreement.
 
  2D: E1 = 0.10707 The Fermi-Dirac integral F-1/2 (which includes the Gamma prefactor 
of the Fermi-Dirac integral) at position (x=22.5 nm,y) can be 
evaluated to: F-1/2 [ 
(EF(x,y) - E1)/ (kBT) ] = F-1/2 [ 
-4.141821 ] = 0.015717538 The maximum value of |Psi1(x=22.5 nm,y)|² is 0.04265 1/nm².This value, multiplied with the length of 5 nm (extension along the y 
  direction) leads to 0.21325 1/nm and compares well with the 1D result of 
  0.21324 1/nm.
 => n(x = 22.5 nm,y) = 1/2 * 2 * (0.067)1/2 * 2.323704676*108 1/m * 0.04265 1/nm² * 
0.015717538 = 0.040320 * 1024 1/m³ = 0.04032 * 1018 1/cm³                                                                                                        If 
F-1/2 were  
0.094843, then the 2D result would be the same as the 1D one. conduction band minimum: 0.03156 eV, conduction band maximum: 0.22592 eV (k.p leads to the same density.) 
1D: E1 = 0.10707 The logarithm at position x can be simplified to: ln(1 + exp(- 0.10707 / 0.025852)) = 
ln 1.0159 = 0.01577 Psi1²(x = 22.5 nm) = 0.21324 1/nm => n(x = 22.5 nm) = 0.067 * 1.07992*1017 1/m² * 0.21324 1/nm * 
0.01577 = 2.43311 * 1022 1/m³ =  0.02433 * 1018 1/cm³ conduction band minimum: 0.03156 eV, conduction band maximum: 0.22592 eV 
  (For this tutorial example, we used k-range-determination-method =
bulk-dispersion-analysis as here the automatic determination of k-range works well because 
the in-plane dispersion is the same as the bulk k.p dispersion. Note: The 
new input files use 'k-max-input' 
instead.) Comments: It seems that for 2D and "box" (single-band) 
the results are slightly different compared to 2D and "box-integration" (8-band 
k.p).This is a bit strange. The former results are a bit strange. This should be 
checked.
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