| nextnano3 - Tutorialnext generation 3D nano device simulator1D TutorialSolution of the Poisson equation for different charge density profilesAuthor:
Stefan Birner If you want to obtain the input files that are used within this tutorial, please 
check if you can find them in the installation directory.If you cannot find them, please submit a
Support Ticket.
 
 1) -> 1D_Poisson_dipole.in / *_nnp.in - input file for the nextnano3 and nextnano++ software 
(1D simulation)2) -> 1D_Poisson_linear.in
 3) -> 1D_Poisson_delta.in
 
 
 1) Dipole: Constant charge density profile of positive and 
negative charge
 2) Linear charge density profile of positive and negative 
charge
 
 3) Delta-function like charge density profile of positive and 
negative charges
   The following figures show a dipole charge density distribution where
 - the left   region carries a constant positive  
charge density (resulting from ionized donors     ND+) 
and
 - the right region carries a constant negative charge density 
(resulting from ionized acceptors NA-).
 Left figure:
   1Ddoping_concentration.datRight figure:
  densities/density1Dspace_charge.dat
 
    
 We have to solve the Poisson equation: d2phi / dx2 
=
 -rho / (epsilon epsilon0)
 The following figures shows the corresponding electric field distribution (left) 
and the electrostatic potential (right).
 
 Left figure:
   band_structure/electric_field1D.datRight figure:
  band_structure/potential1D.dat
 
    
 The electric field is given by E(x) =
 -dphi / dx and 
has a linear dependence (~-x) because the electrostatic potential 
has a quadratic dependence (~ x2).
 The maximum value of the electric field is given by:
 
 Emax = rho / (epsilon epsilon0) * x0 = e * 1*1018 
cm
 -3 / ( 12.93 * 8.8542*10-12 As/Vm 
) * 10 nm == 1.3995*107 V/m = 139.95 
kV/cm
 where x0 is the width of the positive (or negative) charge 
density region, and epsilon = 12.93 is the static dielectric constant of GaAs.
 
 The drop of the electrostatic potential between 0 nm and 20 nm is simply given 
by the area that is below the graph of the electric field:
 
 Delta phi = 1/2 Emax * 20 nm = 
139.95 mV
     The following figures show a linearly varying charge density distribution 
where
 - the left   region carries a linearly decreasing 
positive  charge density (resulting from ionized donors     
ND+) and
 - the right region carries a linearly increasing  negative 
charge density (resulting from ionized acceptors NA-).
 Left figure:
   1Ddoping_concentration.datRight figure:
  densities/density1Dspace_charge.dat
 
    
 The following figures shows the corresponding electric field distribution (left) 
and the electrostatic potential (right).
 
 Left figure:
   band_structure/electric_field1D.datRight figure:
  band_structure/potential1D.dat
 
    
 The electric field shows a quadratic dependence  (~
 -x2) 
whereas the electrostatic potential shows a cubic dependence (~ x3).   The following figures show a delta-function like charge density distribution 
where
 - in the middle       of the 
structure there is a constant positive  charge density   of width 
1 nm         (resulting from ionized 
donors     ND+) and
 - at the boundaries of the structure there are constant negative 
charge densities of width 1 nm each (resulting from ionized acceptors NA-).
 Left figure:
   1Ddoping_concentration.datRight figure:
  densities/density1Dspace_charge.dat
 
    
 The following figures shows the corresponding electric field distribution (left) 
and the electrostatic potential (right).
 
 Left figure:
   band_structure/electric_field1D.datRight figure:
  band_structure/potential1D.dat
 
    |